async await

Question

What does the code snippet to the right output by console.log?

Snippet

async function async1(){
  console.log(1)
  await async2()
  console.log(2)
}

async function async2(){
  console.log(3)
}

console.log(4)

setTimeout(function(){
  console.log(5)
}, 0)

async1()

new Promise(function(resolve){
  console.log(6)
  resolve()
}).then(function(){
  console.log(7)
})

console.log(8)

Source

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